Calculate your expected winnings (or losses) if you throw away all but the J♦ and K♣. This means you get rid of 4♦, 5♠, 6♠. You might get a pair, 2-pair, 3-of-a-kind, 4-of-a-kind, full house, straight, or nothing. We will let R be the set of cards {2,3,7,8,9,10,Q,A} and S be the set of {4,5,6} that don't include 4♦, 5♠, 6♠.
pair of kings or pair of jacks (this is the same for either one so we just think of how we do the jacks and multiply by 2): one other J and two other cards that don't make a pair.
the two cards are from R, or
one card is from R and one from S, or
both cards are from S
pair of queens or aces (this is the same for either one so we just consider how we do the queens and multiply by 2): this includes 2 queens, J♦ and K♣, and one card from the other 37 cards
two pair incl jacks: one pair of jacks (incl J♦), one pair from R, last card is the K♣.
two pair incl kings: one pair of kings (incl K♣), one pair from R, last card is J♦.
two pair incl jacks: one pair of jacks (incl J♦) one pair from S, last card is K♣.
two pair incl kings: one pair of kings (incl K♣), one pair from S, last card is J♦.
two pair; one of jacks and one of kings: one pair of jacks (incl J♦), one pair of kings (incl K♣) and one card from the remaining 41 cards
3-of-a-kind jacks or 3-of-a-kind kings (this is the same for either one so we decide how to do the jacks and multiply by 2): the J♦ and two more jacks, the K♣, and one more card from the remaining 41.
3-of-a-kind from R plus the J♦ and K♣.
3-of-a-kind from S plus the J♦ and K♣.
4-of-a-kind kacks plus the K♣.
4-of-a-kind kings plus the J♦.
full house with 3 jacks and 2 kings
full house with 2 jacks and 3 kings
straight K high: one of each 9,10,Q
straight A high: one of each 10,Q,A
nothing: can be found by taking C(47,3) minus all previous hands OR
three different cards from R (remove all possible straights)
two different cards from R, one from S
one card from R, two different cards from S
three different cards from S
pair of 4s or pair of 5s or pair of 6s and one other card from the remaining 38
pair from {2,3,7,8,9,10} and one other card from the remaining 37